NH3 is produced according to the following reaction: N2 (g) + 3H2 (g)→ 2NH3 (g) In an experiment, 0.25 mol of NH3 is formed when 0.5 mol of N2 is reacted with 0.5 mol of H. What is the % yield?
Correct answer: A. 75%
- A. 75%
- B. 50%
- C. 33%
- D. 25%
Explanation
Following is the solution to this question:% yield = produced mol of NH3×100 max. possible produced mole of NH3=0.250.5×23×100=75%
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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