The state of hybridization of carbon atom in ethane is:
Correct answer: A. Sp³
- A. Sp³
- B. Sp²
- C. Sp
- D. dsp³
Explanation
The hybridization of carbon atoms in ethane is SP3. This is because each carbon atom in ethane forms four covalent bonds, which require four orbitals with equal energy. The SP3 hybrid orbitals are formed by the combination of one S orbital and three P orbitals of carbon atom. The resulting hybrid orbitals have a tetrahedral geometry with an angle of 109.5 degrees between each bond.
Last updated
About Fundamental Principles of Organic Chemistry
Organic chemistry begins with carbon compounds classified by carbon skeleton, saturation and functional group. Work includes identifying groups such as hydroxyl, carbonyl, carboxyl and amino, applying basic nomenclature, and distinguishing structural, geometric and optical isomers, where the same molecular formula does not necessarily mean the same structure or properties.
Practise Fundamental Principles of Organic Chemistry
536 free Fundamental Principles of Organic Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.