Moderate

The speed V of the waves in the string depends upon the tension F of the string and m, the mass per unit length of the string. It is given by:

Correct answer: A. V2=F/m

  • A. V2=F/m
  • B. V=F/m
  • C. V*m=F
  • D. V= F*m

Explanation

Option A: V^2 = F/m: This equation suggests that the square of the wave speed (V^2) is equal to the tension (F) divided by the mass per unit length (m). Hence, this equation is correct. Option B: It states that the wave speed (V) is equal to the tension (F) divided by the mass per unit length (m). This equation reflects the direct proportionality between wave speed and tension, while inversely proportional to the mass per unit length. However, the correct relation should have either V^2 or square root of F/m.Option C: V * m = F: This equation suggests that the product of wave speed (V) and the mass per unit length (m) is equal to the tension (F). However, this equation is not correct. The correct equation does not involve multiplication between wave speed and mass per unit length.Option D: V = F * m: This equation suggests that the wave speed (V) is equal to the product of tension (F) and mass per unit length (m). However, this equation is not correct. The correct equation involves dividing the tension by the mass per unit length, not multiplying them.

Last updated

About Simple Harmonic Motion

Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.

Practise Waves

1,281 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Exams that ask Physics questions like this

Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

Related questions