Calculate the frequency if the number of revolutions is 300 and the paired poles are 50.
Correct answer: A. 15 kHz
- A. 15 kHz
- B. 150 kHz
- C. 1500 kHz
- D. 150 Hz
Explanation
Correct option is A.We know thatF = p × nF = 50 × 300F = 1500 Hz = 15 kHzAs this is a numerical thus only one option is correct.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
Practise Waves
1,289 free Waves MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Simple Harmonic Motion questions
A spring of force constant 400 N/m has an extension of 5 cm, the work done in extending it from 5 cm to 15 cm is:
Maximum acceleration with zero velocity is possible only for:
At which of the following places, the motion of a simple pendulum become slowest:
A first harmonic stationary sound wave is produced in the air of a cylinder that is half-filled with water. More water is added to the cylinder. Now the first harmonic stationary wave is produced with a different frequency. What are the changes in frequency and the nature of displacement in the air at the water surface?
The speed V of the waves in the string depends upon the tension F of the string and m, the mass per unit length of the string. It is given by:
A simple pendulum has mass M, length L, and time period T. What is the period of oscillation of the pendulum with mass 4M and length 0.49L?