The spectral line of the shortest wavelength in Balmer series of atomic hydrogen will be :
Correct answer: D. 3647 A0
- A. 4215 A0
- B. 1437 A0
- C. 3942 A0
- D. 3647 A0
Explanation
Shortest wavelength means maximum energy. Therefore, the electronic transition involved should be :
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Atomic structure covers the discovery of the proton, Planck's quantum theory, hydrogen emission spectra and the evidence for quantized energy levels. You will use quantum numbers to describe orbitals, distinguish s, p, d and f orbital shapes, and write electronic configurations, including the correct order of electron filling.
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