The e/m ratio of cathode rays is:
Correct answer: B. 1.76 x 10^11 C/kg
- A. 1.76 x 10^23 C/ kg
- B. 1.76 x 10^11 C/kg
- C. 1.76 x 10^-31 C/kg
- D. 1.76 x 10^7 C/kg
Explanation
Option B is correct.The e/m ratio of cathode rays is 1.76 x 10^11 C/kg. This means that the charge-to-mass ratio of the particles that make up cathode rays is 1.76 x 10^11 coulombs per kilogram. Cathode rays are beams of electrons that are produced when a high voltage is applied to a gas in a vacuum tube. The electrons are accelerated by the electric field, and they travel in straight lines through the gas. The e/m ratio of cathode rays was first measured by J.J. Thomson in 1897. Thomson's experiment showed that the e/m ratio of cathode rays is independent of the gas that is used in the vacuum tube. This led Thomson to conclude that the particles that make up cathode rays are a fundamental particle of matter, which he called the electron. The e/m ratio of cathode rays is a very important quantity in physics. It is used to determine the mass of the electron, and it is also used to study the properties of electrons.
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