The solubility product of silver iodide is 8.3 x 10^-17 and the standard potential (reduction) of Ag, Ag+ electrode is + 0.800 volts at 25ºC. The standard potential of Ag, AgI -/ I electrode (reduction) from these data is:
Correct answer: D. − 0.15 V
- A. − 0.30 V
- B. + 0.15 V
- C. + 0.10 V
- D. − 0.15 V
Explanation
The correct answer is -0.15 V. To find the standard potential of the Ag, AgI-/I electrode, we use the Nernst equation and consider the solubility product (Ksp) of AgI. The Nernst equation helps relate the concentration of ions in solution to the electrode potential. Given the solubility product of AgI is 8.3x10-17, and the standard reduction potential of the Ag, Ag+ electrode is +0.800 V, we calculate the corresponding reduction potential for the Ag, AgI-/I system by adjusting for the solubility product. The derived potential is -0.15 V. The incorrect options arise from miscalculations or incorrect application of the electrochemical principles.
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