The shortest wavelength radiation in Bracket series has wavelength:
Correct answer: A. 16/R
- A. 16/R
- B. 16RH
- C. RH/16
- D. 4/RH
Explanation
In the Brackett series, all transitions end at n = 4. The shortest wavelength comes from the transition n → ∞ → 4 (the series limit). Using the Rydberg formula: 16/R is the correct option.
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