An electron and a proton are accelerated through the same potential. If their masses are "me" and "mp" respectively, then the ratio of their de-Broglie wave length is:
Correct answer: D. Option D
- A. Option A
- B. Option B
- C. Option C
- D. Option D
Explanation
Both gain the same kinetic energy (eV), so their de-Broglie wavelength depends only on mass:λ = h / √(2m eV)Taking the ratio:λₑ / λₚ = √(mₚ / mₑ)So the electron's wavelength is larger by the square root of the proton-to-electron mass ratio.
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