The ratio of volume between 4 g of H2 and 32g of CH4 at STP is
Correct answer: C. 1:1
- A. 1:2
- B. 1:8
- C. 1:1
- D. 2:1
Explanation
At STP, 1 mole of any ideal gas occupies 22.4 liters. The molar mass of H2 is 2 g/mol, so 4 g of H2 is 2 moles, which occupies 2 x 22.4 = 44.8 liters. The molar mass of CH4 is 16 g/mol, so 32 g of CH4 is also 2 moles, which occupies 44.8 liters as well. Therefore, the volume ratio is 1:1. Option C is correct. Other options suggest incorrect volume ratios based on incorrect assumptions about mole calculations or gas behavior at STP.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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