Calculate number of moles of K2SO4 produced when 14g KOH are reacted with excessof H2SO4:
Correct answer: B. 0.125
- A. 0.25
- B. 0.125
- C. 0.50
- D. 1.50
Explanation
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4)and water (H2O) 1. Molar Mass: - Calculate the molar mass of KOH (Potassium Hydroxide) and (Potassium Sulfate). 2. Calculate Moles of KOH - Divide the given mass of KOH (14g) by its molar mass to find the moles of KOH. 14/56= 0.249 moles 3. Use Mole Ratio: - For every 2 moles of KOH in the reaction, 1 mole of (K2SO4) is produced. This is based on the chemical equation. 4. Calculate Moles of (K2SO4): - Multiply the moles of KOH by the mole ratio (1/2) to find the moles of K2SO4 produced. Therefore, when 14g of KOH reacts, approximately 0.125 moles of (K2SO4) are produced under the given conditions.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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