Calculate number of moles of K2SO4 produced when 14g KOH are reacted with excessof H2SO4:

Explanation

The balanced chemical equation for the reaction between potassium hydroxide (KOH) and sulfuric acid (H2SO4) to produce potassium sulfate (K2SO4)and water (H2O) 1. Molar Mass: - Calculate the molar mass of KOH (Potassium Hydroxide) and (Potassium Sulfate). 2. Calculate Moles of KOH - Divide the given mass of KOH (14g) by its molar mass to find the moles of KOH. 14/56= 0.249 moles 3. Use Mole Ratio: - For every 2 moles of KOH in the reaction, 1 mole of (K2SO4) is produced. This is based on the chemical equation. 4. Calculate Moles of (K2SO4): - Multiply the moles of KOH by the mole ratio (1/2) to find the moles of K2SO4 produced. Therefore, when 14g of KOH reacts, approximately 0.125 moles of (K2SO4) are produced under the given conditions.