The rate constant for forward and backward reaction of hydrolysis of esters are 1 x 10^-2 and 2 x 10^-3 respectively. The equilibrium constant of the reaction is:
Correct answer: C. 5
- A. 3
- B. 4
- C. 5
- D. 6
Explanation
The equilibrium constant (K) is defined as the ratio of the rate constants for the forward and backward reactions: K = kf / kb Given that the rate constant for the forward reaction (k_f) is 1 × 10-2 and the rate constant for the backward reaction (k_b) is 2 × 10-3, we can substitute these values into the equation: K = (1 × 10-2) / (2 × 10-3) = 5 Therefore, the equilibrium constant (K) for the hydrolysis of esters is 5.
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About Chemical Equilibrium
Reversible reactions reach dynamic equilibrium when forward and reverse rates become equal, and Le Chatelier's principle predicts the effect of changing concentration, pressure or temperature. The chapter also covers solubility product, the common ion effect, buffer action and the conditions used in Haber's process, with equilibrium shifts distinguished from changes in the equilibrium constant.
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