The primary coil of an ideal transformer has 100 turns and the secondary has 600 turns. Then:
Correct answer: D. The primary current is six times the secondary current
- A. The power in the primary circuit is less than that in the secondary circuit
- B. The currents in the two circuits are the same
- C. The voltages in the two circuits are the same
- D. The primary current is six times the secondary current
Explanation
In this transformer, the primary coil has 100 turns and the secondary coil has 600 turns. Using the relationship between the number of turns and current, we have:Ip/Is = Ns/Np = 600/100 = 6. This indicates that the primary current (Ip) is six times the secondary current (Is), making Option D correct.Options A, B, and C are incorrect. A is wrong because power is conserved in an ideal transformer; B is incorrect as the currents differ due to the turns ratio; and C is wrong since this is a step-up transformer, resulting in different voltages across the coils.
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