If the emf across the conductor of length lm moving with a uniform speed at right angles to a magnetic field of 0.5T is 2V, the velocity of the conductor is:
Correct answer: C. 4ms-1
- A. 1ms-1
- B. 2ms-1
- C. 4ms-1
- D. 8ms-1
Explanation
Explanation is given below: The electromotive force (emf) induced in a conductor moving at right angles to a magnetic field can be calculated using Faraday's law of electromagnetic induction: emf = B * v * L Where: emf = Electromotive force (2V in this case) B = Magnetic field strength (0.5T) v = Velocity of the conductor (which we want to find) L = Length of the conductor (1m) Now, we can rearrange the equation to solve for the velocity (v):v = emf / (B * L) Plugging in the given values:v = 2V / (0.5T * 1m)v = 2V / 0.5Tv = 4 m/s So, the velocity of the conductor is 4 meters per second.
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Magnetic flux density and magnetic flux describe the strength of a magnetic field and the field passing through a surface. A charged particle moving through a magnetic field experiences a force perpendicular to its velocity and may follow circular or helical motion, depending on the angle between velocity and field.
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