A 100-turn coil of area 0.1 m2 rotates at half a revolution per second. It is placed in a uniform magnetic field of 0.01 T perpendicular to the axis of rotation of the coil. Calculate the maximum voltage generated in the coil?
Correct answer: C. 0.314 V
- A. 256.33 V
- B. 89.12 V
- C. 0.314 V
- D. 3.1455 V
Explanation
N=100A=0.1ω= ½ revolutions per second or ω= π radians/second [ as 1 revolution/sec=2πradians/sec]B= 0.01 TAS, Emf E = NωAB sin θ E= [100][π ][0.1][0.01] E= 0.314 V
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