The potential set up when an electrode is in contact with 1M solution of its ions at 298 K is known as standard electrode potential (or standard reduction potential denoted by E°). All of the following statements about standard electrode potential are correct EXCEPT:
Correct answer: D. E°red of Cl2 is maximum (+2.87V)
- A. The smaller the E°red, the greater the reducing power of a metal
- B. E°rcd of Li1 is minimum (-3.04V)
- C. The greater the E°red, the greater the oxidizing power of a non-metal
- D. E°red of Cl2 is maximum (+2.87V)
Explanation
The statement that E°red of Cl2 is maximum (+2.87V) is incorrect. Chlorine has a high E°red because it is a strong oxidizing agent. However, the maximum E°red for any substance is +1.23V, which is the value for fluorine. Therefore, the E°red of Cl2 cannot be greater than +1.23V.
Last updated
About Electrochemistry
Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
Practise Electrochemistry
696 free Electrochemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemistry questions like this
Chemistry is on 12 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
10-2 mole of Fe3O4 is treated with excess KI solution in presence of dilute H2SO4, the products are Fe2+ and I2(g). What volume of 0.1 (M) Na2S2O3 will be needed to reduce the liberated I2(g)?
+3 and +5 oxidation states are often shown by:
3 faraday of electricity is passed through molten Al2O3 , aqueous solution of CuSO4 and molten NaCl taken in three different electrolytic cells. The amount of Al, Cu and Na deposited at the cathodes will be in the ratio of:
5.3 gm of M2CO3 is dissolved in 150 ml of 1N HCl. The unused acid required 100 ml of 0.5N NaOH. Hence equivalent weight of M is:
8H++ MnO4- → Mn2+ + 4H2O , which one is correct about given equation?