The potential gradient between two charged plates having a separation of 0.5 cm and potential difference of 12 volts is
Correct answer: C. 2.4 NC^(-1)
- A. 240 NC^(-1)
- B. 24 NC^(-1)
- C. 2.4 NC^(-1)
- D. 2400 NC^(-1)
Explanation
The potential gradient (electric field) between two charged plates is calculated by dividing the potential difference (voltage) by the separation distance between the plates. In this case, the potential gradient is frac{12V 0.5cm = 24NC^{-1} .
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