The potential difference between two parallel plates is 10⁴ V. If the plates are separated by 0.5 cm, the force on an electron between the plates is:
Correct answer: D. 3.2 x 10⁻¹³ N
- A. 32 x 10⁻¹³ N
- B. 0.32 x 10⁻¹³ N
- C. 0.032 x 10⁻¹³ N
- D. 3.2 x 10⁻¹³ N
Explanation
First, find the electric field E = V/d = 10⁴ V / 0.005 m = 2 x 10⁶ V/m. Then, calculate the force on the electron using F = qE = (1.6 x 10⁻¹⁹ C) × (2 x 10⁶ V/m) = 3.2 x 10⁻¹³ N.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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