The oxidation numbers of the oxygen atom in OF₂ and H₂O₂, respectively, are:
Correct answer: B. +2, -1
- A. -2, -1
- B. +2, -1
- C. -1, +2
- D. +2, +1
Explanation
In OF₂, fluorine is the most electronegative element and is assigned -1, making oxygen +2. In hydrogen peroxide (H₂O₂), hydrogen is +1, which means each oxygen atom must have an oxidation state of -1 to balance the molecule.
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Electrochemistry describes electron transfer through oxidation and reduction, identifies oxidizing and reducing agents, and applies oxidation numbers to balance redox equations. It also covers electrode potential and the standard hydrogen electrode, which provides the reference for comparing the reduction tendencies of other electrodes.
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