The number of moles of Cr2O7 needed to oxidize 0.136 equivalent of N2H5 according to the reaction is: N2H5+ + Cr2O7 2- --> N2Cr3+ + H2O is:
Correct answer: D. 0.0227
- A. 0.136
- B. 0.272
- C. 0.816
- D. 0.0227
Explanation
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About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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