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Number of H+ ions when 0.1 mole of sulphuric acid is completely ionized in water:

Correct answer: D. 2 x 6.022 x 10^22

  • A. 4 x 6.022 x 10^23
  • B. 2 x 6.022 x 10^23
  • C. 1 x 6.022 x 10^23
  • D. 2 x 6.022 x 10^22

Explanation

Option D is correct.When 0.1 mole of sulfuric acid is completely ionized in water, it will produce 2 x 6.022 x 10^22 H+ ions.Sulfuric acid (H2SO4) is a strong acid, which means that it dissociates completely in water. This means that when 0.1 mole of sulfuric acid is dissolved in water, it will produce 0.1 mole of H+ ions and 0.1 mole of SO4^2- ions. Each molecule of sulfuric acid produces 2 H+ ions, so 0.1 mole of sulfuric acid will produce 2 x 0.1 = 0.2 moles of H+ ions. The number of H+ ions is equal to the number of moles of H+ ions, so there will be 2 x 6.022 x 10^22 H+ ions when 0.1 mole of sulfuric acid is completely ionized in water.The answer is 2 x 6.022 x 10^22.

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About Fundamental Concepts of Chemistry

Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.

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