The number of gram molecules of oxygen in 6.02 x 10^24 CO molecules is:
Correct answer: B. 5 gm molecules.
- A. 1 gm molecules.
- B. 5 gm molecules.
- C. 2 gm molecules.
- D. 8 gm molecules.
Explanation
6.0 2 ×10²³ molecules of CO contain 6.023×10²³ molecules of oxygen. 6.02 ×10²³ molecules of CO contain 6.023×10²³ molecules of oxygen. Then 6.02 ×10²⁴ molecule of CO contain 6.02×10²⁴ molecule of oxygen. No. Of gram atom of O=6.02×10²⁴/6.02×10²³ =10gatoms As oxygen is diatomic molecule. No. of gram of molecule of oxygen=10gmatom/2atoms/molecule =5gmolecule Therefore, option B is correct.
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