The number of gram molecules of oxygen in 6.02 x 10^24 CO molecules is:
Correct answer: B. 5 gm molecules.
- A. 1 gm molecules.
- B. 5 gm molecules.
- C. 2 gm molecules.
- D. 8 gm molecules.
Explanation
6.0 2 ×10²³ molecules of CO contain 6.023×10²³ molecules of oxygen. 6.02 ×10²³ molecules of CO contain 6.023×10²³ molecules of oxygen. Then 6.02 ×10²⁴ molecule of CO contain 6.02×10²⁴ molecule of oxygen. No. Of gram atom of O=6.02×10²⁴/6.02×10²³ =10gatoms As oxygen is diatomic molecule. No. of gram of molecule of oxygen=10gmatom/2atoms/molecule =5gmolecule Therefore, option B is correct.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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