A compound has an empirical formula CH2CI, and molecular formula mass as 99gmol-1, identify the compound:
Correct answer: C. C2H4Cl2
- A. C2H4Cl
- B. C4H8Cl
- C. C2H4Cl2
- D. C2H3Cl3
Explanation
Empirical formula mass = 49.5 g Molecular mass = 99 g Therefore n = 2 Therefore molecular formula of compound = (CH2Cl)2 The compound is C2H4Cl2.
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