A compound has an empirical formula CH2CI, and molecular formula mass as 99gmol-1, identify the compound:
Correct answer: C. C2H4Cl2
- A. C2H4Cl
- B. C4H8Cl
- C. C2H4Cl2
- D. C2H3Cl3
Explanation
Empirical formula mass = 49.5 g Molecular mass = 99 g Therefore n = 2 Therefore molecular formula of compound = (CH2Cl)2 The compound is C2H4Cl2.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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