The maximum possible efficiency of a heat engine operating between the temperature limits of 373 K and 673 K as input and output respectively is
Correct answer: B. 44.6%
- A. 25%
- B. 44.6%
- C. 55.4%
- D. 75%
Explanation
The maximum possible efficiency of a heat engine operating between temperature limits is given by the Carnot efficiency formula:Efficiency = 1 - (T-low / T-high)where T-low is the absolute temperature of the colder reservoir (373 K in this case) and T-high is the absolute temperature of the hotter reservoir (673 K in this case).Let's calculate the efficiency using the formula:Efficiency = 1 - (373 K / 673 K)Efficiency = 1 - 0.554Efficiency = 0.446 or 44.6%Therefore, the correct option is B: 44.6%.
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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