The largest number of molecules are present in:
Correct answer: A. 3.6g H2O
- A. 3.6g H2O
- B. 2.8g of CO
- C. 4.8g of C2H5OH
- D. 5.4g of N2O5
Explanation
The largest number of molecules are present in 3.6g of H2O. Mr of H2O= 2x1 + 16 = 18 Mole= Mass/Mr Mole= 3.6/18 = 0.2mol 1mole = 6.02x10^23 molecules 0.2mole =0.2 x 6.02x10^23 molecules x= 1.2x10^23 molecules
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Fundamental Concepts of Chemistry
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
Practise Fundamental Concepts of Chemistry
894 free Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Fundamental Concepts of Chemistry questions
A polymer of empirical formula CH2 has a molar mass of 28000gmol-I. What is its molecular formula?
What is the mass (in grams) of 5 moles of water (H2O)?
1g mole of which pair weighs equal?
The number of molecules in 5.6 dm3 of oxygen under STP conditions is:
10 moles of hydrogen are allowed to react with 6 moles of oxygen. How much water will be obtained from this reaction on complete consumption of one gas?
Mass of NaOH containing 6.02 x 10^23 sodium atoms is: