Mass of NaOH containing 6.02 x 10^23 sodium atoms is:
Correct answer: C. 40 g
- A. 23 g
- B. 4.0 g
- C. 40 g
- D. 20 g
Explanation
NaOH : Na.1 mole : 6.02x1023 atoms40g : 6.02x1023 atoms. The mass of NaOH containing 6.02x1023 sodium atoms is 40 grams.The molar mass of NaOH is 40.00 grams per mole, and 1 mole of NaOH contains 6.02 x 1023 atoms of Na. So, 6.02 x 1023 sodium atoms will be present in 40 grams of NaOH.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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