The kinetic energy of electrons by applying potential difference V1 across the x-ray tube is (KE)1, while the V2 potential difference produces kinetic energy equal to (KE)2. What, will be the value of (KE)1:(KE)2 if the ratio of potential difference V1:V2 = 2:3?
Correct answer: D. 2:3
- A. 3:2
- B. 4:9
- C. 9:4
- D. 2:3
Explanation
Emax(KE) = hfmax = eV, V and KE are in direct relation so V:V and KE:KE ratios would be the same.
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