The K.E. of bullet of mass 500g moving at a speed of 200 ms-1 is:
Correct answer: D. 10000 J
- A. 250 J
- B. 2500 J
- C. 125 J
- D. 10000 J
Explanation
K.E = (1/2)mv^2= (1/2)(0.5)(200)^2 = (1/2)(0.5)(40000)= (1/2)(20000) = 10000 J
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Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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