5.0 kg cart is moving horizontally at 6.0m/s. In order to change its speed to 10.0m/s, the net work done on the cart must be:
Correct answer: B. 160 J
- A. 40 J
- B. 160 J
- C. 90 J
- D. 400 J
Explanation
By work energy principleWork done = Change in kinetic energyWork = (1/2) m vf² - (1/2) m vi² = (1/2) m ( vf² - vi²)= (1/2)(5)(10² - 6²) = (1/2)(5)(64) = 160 J.
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About Work and Energy
Work transfers energy when a force causes displacement, while kinetic energy, gravitational potential energy and power describe motion, position and the rate of energy transfer. The work-energy theorem links net work with change in kinetic energy, and efficiency accounts for energy losses rather than treating them as energy destruction.
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