The ionization energy of a hydrogen atom is 13.6 ev. The ionization potential required will be:
Correct answer: D. 13.6 volt
- A. 4.9 volt
- B. 8.5 * 10-10 volt
- C. 3.4 volt
- D. 13.6 volt
Explanation
The ionization energy of a hydrogen atom is the energy required to remove an electron from the atom. It is given as 13.6 electron volts (eV). When determining the ionization potential, which is essentially the energy needed per electron to remove it from the influence of the nucleus, the same value (13.6 eV) applies. Thus, the ionization potential, when expressed in volts, is also 13.6 volts.Option A (4.9 volts) is unrelated to the ionization energy of hydrogen. Option B (8.5 * 10-10 volts) is incorrectly expressed in scientific notation and is far too small. Option C (3.4 volts) may be relevant to transitions between specific energy levels in hydrogen but is not the ionization potential. Therefore, only Option D correctly matches the ionization energy with the ionization potential at 13.6 volts.
This question appeared on the ETEA MDCAT 2008 paper, which you can sit online with every answer explained.
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The hydrogen spectrum consists of discrete emission lines produced when electrons fall between quantised energy levels and release photons. Questions use the Rydberg equation, photon energy and wavelength, and identify the Lyman, Balmer, Paschen, Brackett and Pfund series, which differ from continuous spectra.
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