Asked in ETEA MDCAT 2008 2008Moderate

The ionization energy of a hydrogen atom is 13.6 ev. The ionization potential required will be:

Correct answer: D. 13.6 volt

  • A. 4.9 volt
  • B. 8.5 * 10-10 volt
  • C. 3.4 volt
  • D. 13.6 volt

Explanation

The ionization energy of a hydrogen atom is the energy required to remove an electron from the atom. It is given as 13.6 electron volts (eV). When determining the ionization potential, which is essentially the energy needed per electron to remove it from the influence of the nucleus, the same value (13.6 eV) applies. Thus, the ionization potential, when expressed in volts, is also 13.6 volts.Option A (4.9 volts) is unrelated to the ionization energy of hydrogen. Option B (8.5 * 10-10 volts) is incorrectly expressed in scientific notation and is far too small. Option C (3.4 volts) may be relevant to transitions between specific energy levels in hydrogen but is not the ionization potential. Therefore, only Option D correctly matches the ionization energy with the ionization potential at 13.6 volts.

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