The energy of an electron in the excited state n=4 in hydrogen atom is:
Correct answer: C. -0.85eV
- A. -13.6eV
- B. -3.4eV
- C. -0.85eV
- D. -1.5eV
Explanation
The energy of an electron in the excited state with n=4 in a hydrogen atom can be calculated by using the formula for the energy levels of hydrogen:E = -13.6eV / n²Substituting n=4 into the formula, we get:E = -13.6 / (4)²E= -13.6 / 16E = -0.85 eV
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The hydrogen spectrum consists of discrete emission lines produced when electrons fall between quantised energy levels and release photons. Questions use the Rydberg equation, photon energy and wavelength, and identify the Lyman, Balmer, Paschen, Brackett and Pfund series, which differ from continuous spectra.
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