The ionic radius of the fluoride ion is:
Correct answer: C. 136 pm
- A. 72 pm
- B. 95 pm
- C. 136 pm
- D. 157 pm
Explanation
The atomic radius of fluorine is 72pm, but when an electron is added, the affective nuclear charge decreases so the ionic radius of an anion is always greater than the atomic radius for fluoride, it is 136pm. Key point: fluoride is the anion of fluorine.
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About s-Block and p-Block Elements
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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