The hybridization of atomic orbitals of N2+, NO3-, and NH4+ are, respectively:
Correct answer: A. sp, sp², sp³
- A. sp, sp², sp³
- B. sp, sp, sp³
- C. sp², sp, sp³
- D. sp², sp³, sp
Explanation
NH4+ has four H atoms bound to a nitrogen atom hence it can be said to be sp3 hybridized. While N2+ is only one bond so we say it is sp hybridized.NO3 has N surrounding 3 O hence it is sp² hybridized. Here's a nice short trick. 1) Count and add all the electrons in valence shell 2) Divide it by 8 3) On dividing by 8 you will get a remainder and quotient, add quotient + (remainder / 2) 4) Now get the hybridization corresponding to the number what you got If 2 its sp,if 3 its sp², if 4 its sp³ , so on.
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