The heat rejected by a Carnot engine operating between 600 K and 300 K with 2000 J of heat input is:
Correct answer: A. 1000 J
- A. 1000 J
- B. 1500 J
- C. 600 J
- D. 1200 J
Explanation
Efficiency of a Carnot engine is η = 1 - (Tcold /Thot ) = 1 - (300/600) = 0.5. Work done is W = η × Qin = 0.5 × 2000 = 1000 J. Heat rejected is Qout = Qin - W = 2000 - 1000 = 1000 J.
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About First Law of Thermodynamics
The first law relates heat supplied, work done and the change in internal energy through energy conservation. Problems use sign conventions and apply the law to isothermal, adiabatic, isobaric and isochoric processes. Internal energy is a state function, while heat and work depend on the path followed.
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