The halogen which reacts spontaneously with gold (Au) to form Au+3 is ________________?
Correct answer: B. Cl2
- A. F2
- B. Cl2
- C. Br2
- D. I2
Explanation
Chlorine reacts directly with gold to form gold(III) chloride: 2Au + 3Cl2 -> 2AuCl3. Fluorine may also form gold(III) fluoride under suitable conditions, but the standard textbook reaction referred to here is the formation of AuCl3 by chlorine.
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About Periodic Properties and Trends
Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
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