The good electron loser elements belongs to group:
Correct answer: A. 1A
- A. 1A
- B. 2A
- C. 3A
- D. 4A
Explanation
Option A is correct since group 1A atoms lose their electron easily because they are large and ionization energy decreases down the groupOption B is incorrect since group 2A will lose electrons less easily than group 1A atoms as they are comparatively smaller than group 1A atoms due to greater nuclear charge across the same period Option C is incorrect since group 3A will lose electrons less easily than even group 2A atoms as they are comparatively smaller than group 2A atoms due to greater nuclear charge across the same period Option C is incorrect since group 4A will lose electrons less easily than even group 3A atoms as they are comparatively smaller than group 3A atoms due to greater nuclear charge across the same period
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Chemical bonding explains molecular shape through VSEPR theory and distinguishes sigma bonds from pi bonds. Questions involve hybridization, bond angles, dipole moment and bond energy, including how electron-pair repulsion determines geometry and how bond polarity differs from the overall polarity of a molecule.
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