The given diagram indicates the energy levels of certain atom.When an electron moves from 2E level to E level, a photon of wavelength λ is emitted.The wavelength of photon emitted during its transition from 4E/3 level to E level is:
Correct answer: D. 3λ
- A. λ/3
- B. 3λ/4
- C. 4λ/3
- D. 3λ
Explanation
According to given conditions; hv = 2E - E → E = hc/λ Also, wavelength of photon when transition occurs, from 4E/3 level to E level → hc/λ1 = 4E/3 - E/3 → λ1 = (hc * 3./E = 3λ
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