The binding energy of an electron in the ground state of the He atom is equal to 24.6 eV. The energy required to remove both electrons from the atom will be:
Correct answer: C. 79 eV
- A. 59 eV
- B. 81 eV
- C. 79 eV
- D. None of these
Explanation
The energy to remove the first electron (first ionization energy) is given as 24.6 eV. The energy to remove the second electron from the resulting He⁺ ion is the second ionization energy, which is 54.4 eV. The total energy required to remove both is the sum: 24.6 eV + 54.4 eV = 79 eV.
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