The Fx component of a force vector 'F' of magnitude 30N make an angle of 60° with X-axis is:
Correct answer: B. 15N
- A. 7N
- B. 15N
- C. 5N
- D. 10N
Explanation
To find the x-component of a force vector 'F' given its magnitude and the angle it makes with the x-axis, we can use the formula: F_x = F * cos(θ) In this case, the magnitude of the force vector 'F' is 30N and it makes an angle of 60° with the x-axis. So, using the formula, we can calculate the x-component as: F_x = 30N * cos(60°) F_x = 30N * 0.5 F_x = 15N Therefore, the x-component of the force vector 'F' is 15N.
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About Vectors and Equilibrium
Vectors have magnitude and direction, unlike scalars, and are combined by head-to-tail or parallelogram methods. Work covers rectangular components, equilibrium when the resultant force is zero, the scalar product for work and projections, and the vector product for torque and cross-product direction using the right-hand rule.
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