The enol form of acetone (CH₃COCH₃) is:
Correct answer: A. CH₂=C(OH)CH₃
- A. CH₂=C(OH)CH₃
- B. CH₃CH=CHOH
- C. CH₂=CH-O-CH₃
- D. HOCH₂-CH=CH₂
Explanation
Tautomerization of acetone involves the removal of a proton from one of the α-carbons and its placement on the carbonyl oxygen, along with a shift of the pi bond. This results in the formation of the enol, prop-1-en-2-ol, which has the structure CH₂=C(OH)CH₃.
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Aldehydes and ketones contain the polar carbonyl group, but aldehydes are generally more readily oxidised and more reactive than ketones. Coverage includes preparation by oxidation or reduction routes, nucleophilic addition of reagents such as hydrogen cyanide and bisulfite, and tests that distinguish aldehydes from ketones.
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