2-Butanone on oxidation with K2Cr2O7 / H2SO4 forms:
Correct answer: D. Propanoic acid & Methanoic acid
- A. Acetic acid
- B. Acetic acid & Ethane
- C. Methane & Propanoic acid
- D. Propanoic acid & Methanoic acid
Explanation
2-Butanone is a methyl ketone (CH₃-CO-CH₂-CH₃).On oxidation with K2Cr2O7 /H2SO4, the ketone undergoes cleavage at the carbonyl, forming propanoic acid (CH₃-CH₂- COOH) and methanoic acid (H-COOH).This is a typical reaction of methyl ketones with strong oxidizing agents.
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About Aldehydes and Ketones
Aldehydes and ketones contain the polar carbonyl group, but aldehydes are generally more readily oxidised and more reactive than ketones. Coverage includes preparation by oxidation or reduction routes, nucleophilic addition of reagents such as hydrogen cyanide and bisulfite, and tests that distinguish aldehydes from ketones.
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