2-Butanone on oxidation with K2Cr2O7 / H2SO4 forms:
Correct answer: D. Propanoic acid & Methanoic acid
- A. Acetic acid
- B. Acetic acid & Ethane
- C. Methane & Propanoic acid
- D. Propanoic acid & Methanoic acid
Explanation
2-Butanone is a methyl ketone (CH₃-CO-CH₂-CH₃).On oxidation with K2Cr2O7 /H2SO4, the ketone undergoes cleavage at the carbonyl, forming propanoic acid (CH₃-CH₂- COOH) and methanoic acid (H-COOH).This is a typical reaction of methyl ketones with strong oxidizing agents.
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