Asked in ETEA MDCAT 2006 2006Moderate

The emf of a galvonic cell can be calculated from:

Correct answer: D. The values of the half cell

  • A. The size of the electrode
  • B. The pH of the solution
  • C. The amount of metal in the anode
  • D. The values of the half cell

Explanation

For a galvanic cell, emf can be calculated by standard reduction potentials for two half cells. Emf is independent of pH except for the reactions involving H+ or OH- ions.Emf is independent of shape and size of electrodes,distance between electrodes and the amount of electrolyte.

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About Standard Hydrogen Electrode

The standard hydrogen electrode provides the reference potential of 0.00 V for measuring electrode potentials. It consists of platinum in contact with hydrogen gas at standard pressure and hydrogen ions at standard concentration, usually at 25°C, and can operate as either the oxidation or reduction half-cell.

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