The electric field between the oppositely charged plates of surface charge density σ is σ/ ϵ0 . If one of the plates is removed, then the electric field becomes
Correct answer: C. σ/2εo
- A. zero
- B. 2σ/εο
- C. σ/2εo
- D. σ/4εο
Explanation
When one of the oppositely charged plates is removed, the electric field between them no longer exists. Therefore, the field becomes half of what it was before removal.Incorrect options: (a), (b), (d) These options do not accurately represent the change in the electric field when one of the plates is removed.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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