The electric field between the oppositely charged plates of surface charge density σ is σ/ ϵ0 . If one of the plates is removed, then the electric field becomes

Correct answer: C. σ/2εo

  • A. zero
  • B. 2σ/εο
  • C. σ/2εo
  • D. σ/4εο

Explanation

When one of the oppositely charged plates is removed, the electric field between them no longer exists. Therefore, the field becomes half of what it was before removal.Incorrect options: (a), (b), (d) These options do not accurately represent the change in the electric field when one of the plates is removed.

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