Capacitance with air is 10 F. If a dielectric of εr =100 is inserted, then the new capacitance is
Correct answer: A. 1000 F
- A. 1000 F
- B. 1000 nF
- C. 10 nF
- D. 100 F
Explanation
The new capacitance with the dielectric inserted is given by C′=εr ×C. Here, εr =100 and C=10 F. So, C′=10:0×10=1000 F.Incorrect options: (b), (c), (d) These options don't accurately reflect the effect of the dielectric on the capacitance.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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