The efficiency of a full wave rectifier circuit is almost ------ than half wave rectifier circuit.
Correct answer: D. double
- A. Four times
- B. same as
- C. Sixteen times
- D. double
Explanation
Efficiency (η) = DC Power Output / AC power inputTherefore, the efficiency of a full wave rectifier (ηf) is 81.2% (calculated)And, the efficiency of a half-wave rectifier (ηh) is 40.6% (calculated)ηh/ηf=40.6/81.2 = 1/2∴ηf=2ηhHence, the efficiency of a full-wave rectifier is double of half wave-rectifier.
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A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
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