The efficiency of a full wave rectifier circuit is almost ------ than half wave rectifier circuit.
Correct answer: D. double
- A. Four times
- B. same as
- C. Sixteen times
- D. double
Explanation
Efficiency (η) = DC Power Output / AC power inputTherefore, the efficiency of a full wave rectifier (ηf) is 81.2% (calculated)And, the efficiency of a half-wave rectifier (ηh) is 40.6% (calculated)ηh/ηf=40.6/81.2 = 1/2∴ηf=2ηhHence, the efficiency of a full-wave rectifier is double of half wave-rectifier.
Last updated
About Electronics
A p-n junction forms when p-type and n-type semiconductor regions meet, creating a depletion layer, barrier potential and rectifying action. The work covers forward and reverse bias, junction current, diode characteristics, and how a diode converts alternating current into pulsating direct current through half-wave and full-wave rectification.
Practise Electronics
660 free Electronics MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Physics questions like this
Physics is on 13 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
Related questions
(7) In n-p-n transistor, p works as: (Tag: Electronics sub-tag: Transistors )
A capacitor and an inductor are connected to the A.C. supply. If we double the frequency of the A.C. supply then the effect on the reactance of capacitor XC and reactance of inductor XL will be:
A capacitor is to be used to provide smoothing for a half wave rectifier. In which of the following diagrams is capacitor correctly connected?
A changing electric flux develops in the region:
A circuit that adds positive or negative voltage to an input sine wave is called _.