The de Broglie wavelength of a particle of mass 1 gram and velocity 100 ms-1 is:
Correct answer: C. 6.63 x 10^-33
- A. 6.63 x 10^-35
- B. 6.63 x 10^-34
- C. 6.63 x 10^-33
- D. 6.63 x 10^-32
Explanation
.de Broglie reasoned that matter also can show Wave-particle duality just like light, since light can behave both as a wave (it can be diffracted and it has a wavelength) and as a particle (it contains packets of energy hν). And also reasoned that matter would follow the same equation for wavelength as light namely, λ = h / p Where p is the linear momentum, as shown by Einstein. P=mv The de Broglie wavelength formula: λ=h/mv h=Plank's constant = 6.63x10-34 m=1g=10-3kg ( 1/1000) v=100m/s λ=h/mv λ=6.63x10-34/ 10-3x100 = 6.63x10-33m
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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