If we use a light of photons having energy 2.4 eV then the stopping potential required will be:
Correct answer: A. 2.4 V
- A. 2.4 V
- B. 2.6 V
- C. 2.5 V
- D. 0 V
Explanation
The formula for stopping potential is: K.Emax=leV0l Rearranging: V0= K.Emax/e =V0= 2.4ev/e V0=2.4 V answer! Stopping potential is defined as the potential required to stop the ejection of electrons from a metal surface when an incident beam of energy greater than the work potential of metal is directed on it. Stopping potential can never be zero.
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Classical physics cannot explain blackbody radiation and related observations, leading to Planck’s quantum theory, in which energy is emitted or absorbed in discrete packets. Photons provide the particle model of light, with energy and momentum linked to frequency and wavelength, including the photoelectric effect and its threshold frequency.
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