The coulombs force between two point charges, If magnitude of each charge is doubled and distance between charges is halved, the force between them becomes:
Correct answer: D. 16F
- A. F
- B. 8F
- C. 4F
- D. 16F
Explanation
The force is F ∝ (q₁q₂)/r². The new force F' will have a factor of (2×2) in the numerator from doubling the charges and a factor of (1/2)² = 1/4 in the denominator from halving thedistance. This gives F' ∝ 4 / (1/4) = 16. The force becomes 16 times greater.
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Electrostatics describes forces between charges through Coulomb's law, electric fields and field intensity, then uses electric potential to measure energy per unit charge. Capacitors store charge and electrical energy, with capacitance depending on geometry and dielectric material, not simply on the amount of charge present.
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