The correct order of ionic radii for the following ions is
Correct answer: D. P3- > S2- > Cl- > K+
- A. S2- < P3- < Cl- < K+
- B. Cl- > S2- > P3- > K+
- C. K+ > Cl- > S2- > P3-
- D. P3- > S2- > Cl- > K+
Explanation
The correct order of ionic radii is P3- > S2- > Cl- > K+. The size of an ion is affected by its electron count and nuclear charge. P3- has the most electrons and least nuclear pull per electron, making it the largest. S2- follows, being larger than Cl- due to its higher negative charge. Cl- is larger than K+ because K+ has lost an electron, resulting in a smaller ionic radius due to increased effective nuclear charge.
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About Periodic Properties and Trends
Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
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