The correct decreasing order of reactivity of alkenes towards hydrogen halides is:
Correct answer: A. 2-Methylpropene > Propene > Ethene
- A. 2-Methylpropene > Propene > Ethene
- B. Ethene > Propene > 2-Methylpropene
- C. Propene > Ethene > 2-Methylpropene
- D. Ethene > 2-Methylpropene > Propene
Explanation
The reaction proceeds via a carbocation intermediate. The more stable the carbocation formed, the faster the reaction. 2-Methylpropene forms the most stable tertiary carbocation, followed by propene (secondary), and then athene (primary). so the reactivity order is 2-Methylpropene > Propene > Ethene.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
Practise Chemistry of Hydrocarbons
1,091 free Chemistry of Hydrocarbons MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Chemistry questions like this
Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Chemistry of Hydrocarbons questions
Which of the following compounds reacts with ammoniacal AgNO3 to form a precipitate?
Sabatier Senderens reaction is an example of:
The number of isomers for the aromatic compound of the formula C7H8O is:
2-methyl propene is isomeric with but-1-ene. They can be distinguished by:
In the presence of peroxide, hydrogen chloride and hydrogen iodide do not give anti-Markovnikov's addition to alkenes because:
What will be formed in the following Kolbe's electrolysis of an aqueous solution of potassium maleate ?